* 获取数字的第digit位(从右往左,0表示个位)
Now that we can build the tree, let's use it to search. Finding a specific point means starting at the root and asking: which child quadrant contains this coordinate? Then you recurse into that child and ask again. Each level of the tree cuts the search space by roughly three-quarters.
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Not the day you're after? Here's the solution to yesterday's Connections.